8x^2+37x=15

Solution for 8x^2+37x=15 equation:

8x^2+37x=15

We move all terms to the left:

8x^2+37x-(15)=0

a = 8; b = 37; c = -15;
Δ = b2-4ac
Δ = 372-4·8·(-15)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-43}{2*8}=\frac{-80}{16}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+43}{2*8}=\frac{6}{16}
=3/8
$